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GRE Practice - Data Interpretation - Set 10

Data Interpretation-10-2
Data Interpretation-10-3-2
  1. The data supports which of the following statements for the period shown?
    Select all that apply.
  1. The average student’s tuition expenses increased each year.
  2. The average student’s rent expenses increased each year.
  3. The average student’s total expenses for food, rent, and tuition combined increased each year.
  1. The average student’s tuition expenses remained the same in 2018 and 2019.
  2. The average student’s rent expenses increased each year. TRUE
  3. The average student’s total expenses for food, rent, and tuition combined increased each year TRUE
  1. By approximately what percent did the average student’s tuition increase from 2016 to 2019?
  1. 9%
  2. 10%
  3. 11%
  4. 17%
  5. 20%

The tuition in 2016 was 27,000 and in 2019 it was $30,000
Increase = 30,000 – 27,000 = 3,000
% increase = 3000/27000 x 100 = 11.11%

  1. Considering the costs of tuition and accommodation only, the average student’s expenses increased by an average of how much per year over the period shown?
  1. $950
  2. $1000
  3. $1050
  4. $1200
  5. $1250

In 2016 the costs of tuition and accommodation only was $31,000 while in 2019 the costs of tuition and accommodation only was $36,000
There has been an increase of $5000 over 4 years = $1250 per year.

  1. What was the average college tuition fees in 2019?
  1. $30,000
  2. $14,400
  3. $27,000
  4. $21,600
  5. $24,000

In 2019, students spent $30,000 on tuition of which 72% was spent on college tuition fees = 72/100 x 30000 = $21,600

  1. In 2019, the cost of Books and Periodicals was what percent of the student’s total expense?
  1. 9.73%
  2. 11.59%
  3. 12.28%
  4. 13.33%
  5. 16.67%

In 2019, students spent a total of $44,000 at University.
Of this $30,000 was spent on tuition and Books and Periodicals accounted for 17% of that $30,000
= 17/100 x 30,000 = $5,100
So the percentage expense on Books & Periodicals was 5100/44000 x 100 = 11.59%

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Q. If the function f(x) is defined as f(x) = 3(x + 1) + 7, then f(a − 2) =

  1. 3a + 5
  2. 3a – 9
  3. 3a + 10
  4. 3a – 4
  5. 3a + 4
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