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Ignore the signs to start with
(-2)a(4)b = 26
(-2)a(2)2b = 26
a + 2b = 6
Possibilities are a=0 and b = 3 or a=2 and b=2 or a = 4 and b = 1
There are 3 cases and a is lesser than, equal to, and greater than in each case respectively.
The sector has a central angle of 900 so it represents ¼ of the circle.
Area of sector = ¼ π r2
Area of isosceles right triangle AOB = ½ x r x r = ½ r2
Area of shaded region = Area of sector – area of ΔAOB = r2( π/4 – ½)
Area of shaded region = ¼ r2( π – 2)
But, area of shaded region = 9(π – 2), ¼ r2= 9 or r = 6
2x+3y = 29, so x+ 3y = 9
Now, x and y are positive integers
So the possibilities are x = 6 and y = 1 OR x = 3 and y = 2
So, 2x+y = 27 OR 25
Quantity A is either 128 or 32; in either case it’s greater than 16
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