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Set the quadratic equal to zero: x2 + 11x + 28 = 0.
We factorize it: (x + 4)(x + 7) = 0.
There are two solutions:
EITHER (x + 3) = 0 and x = –3
OR (x + 4) = 0 and x = –4
Since both solutions are negative, x < 0 and –x > 0.
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